From: Eberhard S. <esc...@ca...> - 2018-02-20 15:07:30
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The use of wtlevel is for cutting off powers in polynomials. You seem to be after a power series expansion around delta=0 of your expression. So you can for example go taylor((-sqrt(-delta^2+epsilon^2)+epsilon)/delta,delta,0,1); 1 2 -----------*delta + O(delta ) 2*epsilon Eberhard On 02/20/2018 10:02 AM, Rudolf Sykora wrote: > Hello, > > for > > j:=((-sqrt(-delta^2+epsilon^2)+epsilon)/delta) > weight delta=1$ wtlevel 1$ j; clear delta$ > > I get > > ( - abs(epsilon) + epsilon)/delta > > while I'd like to get sth. like > > delta / (2 epsilon) > > Am I doing sth. wrong? > Can I somehow enter any 'assumptions', like > > epsilon > delta > 0 > > ? > > > Thanks > Ruda > > ------------------------------------------------------------------------------ > Check out the vibrant tech community on one of the world's most > engaging tech sites, Slashdot.org! http://sdm.link/slashdot > _______________________________________________ > Reduce-algebra-developers mailing list > Red...@li... > https://lists.sourceforge.net/lists/listinfo/reduce-algebra-developers |