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Output declaration 'order' not applied to operator arguments?

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Co-Processor
2020-09-24
2020-09-25

  • Co-Processor

    Co-Processor - 2020-09-24

    A minor thing: after declaring order x,t the output of x-t remains x-t. But f(x-t) (having declared operator f) still becomes f(-t+x). Is this by intention?

     

  • Eberhard Schruefer

    Eberhard Schruefer - 2020-09-24

    I can't reproduce what you are reporting. I get

    1: operator f;

2: f(x-t);

f( - t + x)

3: order x,t;

4: f(x-t);

f(x - t)

    Waht is your version of REDUCE?
    Eberhard

     

    • Co-Processor

      Co-Processor - 2020-09-25

      Thank you for looking into this. I am using the CSL version, revision 5368, from June this year. See attached screen shot.
      Wolfgang

       
      Thumbnail
      reduce_order.png

  • Eberhard Schruefer

    Eberhard Schruefer - 2020-09-25

    Thanks. Now I see. The problem occurs when using the GUI. It is o.k. with the CLI as I had shown. We will investigate the issue.
    Eberhard

     

  • Eberhard Schruefer

    Eberhard Schruefer - 2020-09-25

    I just commited a fix that cures the problem to sourceforge. It will be contained in the next snapshot.

    Eberhard

     

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