Re: [Mingw-users] -march tag in GCC

[Earnie <ea...@us...>]

Fabian Greffrath wrote:
> Am 01.12.2011 09:20, schrieb Tor Lillqvist:
>> Yes and no. The fact that gcc produces assembler source code output
>> that needs to be compiled by a separate assembler pass is not that
>> relevant here. Even if gcc produced object code directly, of course an
>> -march switch would be needed, in the cases where gcc is configured to
>> target a family of several slightly different instruction sets.
> 
> Yes, but if your code is already in assembler you actually tell the 
> CPU exactly which instructions to perform. There is no way for the 
> compiler to chose e.g. using cmov if you enable it via -march flag.

I'm asking because of something like the following code.  If you ``gcc
-march=i386'' it will compile into an object.  If you ``gcc -march=i386
-Wa,-march=i386'' it will abort and not create the object.  My question
is still needing answered, is ``gcc -march=i386'' supposed to propagate
to the assembler compile phase?

void foo (void)
  { __asm__ ( "fninit" ) ;}

-- 
Earnie
-- https://sites.google.com/site/earnieboyd/