#518 PHP Parser throws error with "if ($baz && $foo = bar())"

[scragz]

if ($foo = bar()) {
// ...
}

I realize that it's kind of funky code, but it's
technically correct and can be useful.

[scragz]

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Wait, that wasn't quite right. I was tryng to distill my
real code sample but the sample above does work. It only
seems to mess up when there's an && like this:

if ($baz && $foo = bar())

[Matthieu Casanova]

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fixed in CVS