[ jEdit-devel ] [ jedit-Bugs-1325082 ] matching word break also matches interior of word

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Bugs item #1325082, was opened at 2005-10-12 10:50
Message generated for change (Comment added) made by sjakob
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Category: search and replace
Group: severe bug
Status: Open
Resolution: None
Priority: 7
Private: No
Submitted By: Alan G (abgrover)
Assigned to: Nobody/Anonymous (nobody)
Summary: matching word break also matches interior of word

Initial Comment:
In 4.2 final

Searching with the regular expressions

\b. or \<. jumps to the beginning of a word, unless the
cursor is already in a word, in which case it finds the
next character within the word.

This makes it impossible to replace characters only at
the beginning of a word.

For instance:

search on
\<.

replace with BeanShell snippet
_0.toLowerCase()

should force the first character of every word to be
lower case.  However, it actually forces *every*
character of every word to be lower case.

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>Comment By: Steve Jakob (sjakob)
Date: 2012-01-19 12:15

Message:
I don't think this is a bug. I see 2 issues with Alan G's approach:
1) Note that the boundary matching characters match the boundary and not
the characters themselves. Each word has two boundaries, one BEFORE the
first character and one AFTER the last. Your regex will match the first
boundary of your complete search string, which occurs before the first word
character.
2) The replace string you specify indicates that you want to replace every
character with a lower-case character since "_0" refers to the complete
contents of your searched text. To clarify, if my search text is the string
"this text" Alan's BeanShell snippet is equivalent to "this
text".toLowerCase().

As an alternative, the following appears to work for me:
Search regex: \b(\w)(\w*)
Replace with BeanShell snippet: _1.toLowerCase() + _2

By separating the first character of each word (following a boundary) from
the rest I can transform just that one character.

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Comment By: Robert Schwenn (rschwenn)
Date: 2008-03-02 13:44

Message:
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Originator: NO

The gnu.regex-Package is thrown away now. Not so the bug.

For example:
- The Expression "\b." matches *every* single charcter in a word.
- The Expression ".\b" matches the last charcter in a word (as expected)
but also a following space character.

jEdit 4.3pre12
JRE 1.6.0_03
WinXP SP2


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Comment By: Björn Kautler (vampire0)
Date: 2005-10-12 20:39

Message:
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user_id=918212

As far as I have found, \b, \< and some others are not
supported by the gnu.regex-Package.
One additional point for throwing it away and using
java.util.regex instead. ;-)

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