Re: [Gnuplot-info] format string exclusion

[<seb...@ph...>]

Thanks to both for the ideas.

I thought of changing the date format but the data file I use (a csv file) =

is generated by a monitoring tool
and thus I have no control on it.

Also, since it is a csv file I have defined ',' as the column separator.=20
This prevent me for cheating with the "using"
values.

It looks like I will have to pre-process my file. I will probably use awk=20
to remove one column.
Makes it complicated... ;-)

Thanks again.

regards,
Sebastien





swlab <sw...@co...>
29/12/2004 19:34

=20
        To:     gnu...@li...
        cc:     Sebastien Lemeunier/PH/Novartis@PH
        Subject:        Re: [Gnuplot-info] format string exclusion
        Category:=20



On Wednesday 29 December 2004 12:23, Hans-Bernhard Br=F6ker wrote:
> seb...@ph... wrote:
> > I am fighting in trying to read the standard output of the Unix date
> > command with a timefmt string (e.g. Wed Dec 29 11:26:56 EST 2004).

my 2c:
1. As Hans-Bernhard suggested, choose another timestamp for your 'date'=20
output, for example=20
date +"%d/%m/%Y %H:%M:%S"
"info date" to get more info about the formats you can choose. Might be a=20
problem if your file is already written.
2. Preprocess your file with some scripting language like Perl. There are=20
some=20
extensions developed to process dates, I'm thinking "Date::Manip" in=20
particular, and I'm pretty sure it can recognize your format and output a=20
more suitable one

--=20
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