Re: [Gnuplot-info] Extract filename

[theozh <th...@gm...>]

Thanks, John & Ethan for your immediate response.

> There are some example of gnuplot's strong variable capabilities here that
> should solve your needs.
> http://gnuplot.sourceforge.net/demo/stringvar.html
>

@John, thanks for the link, but strong string variable capabilities? Are
you serious?
It would be nice to find the last key (e.g. '\') in a word. Or at least
a function to reverse a string. Best would be of course regular
expressions ;-).


> Assuming that the subdirectories are not themselves named Datasomething,
Well, I cannot be sure that this will always be the case.

> I'd use something like
> 
>     chop(fullname) = fullname[ strstrt(fullname,"Data") : * ]
> 
>     plot for [FileName in FileList] FileName u 1:2 w l title chop(FileName)
> 
@Ethan, yes, this works with the above mentioned limitations.

Based on your suggestion, the following is a cumbersome workaround for a
function to extract the file name (at least to 6 levels of
subdirectories, but can be extended).


TestFile = 'C:\sub1\sub2\sub3\sub4\Data007.dat'

chop1(FullName) = FullName[strstrt(FullName,'\')+1:*]
chop2(FullName) = chop1(FullName)[strstrt(chop1(FullName),'\')+1:*]
chop3(FullName) = chop2(FullName)[strstrt(chop2(FullName),'\')+1:*]
chop4(FullName) = chop3(FullName)[strstrt(chop3(FullName),'\')+1:*]
chop5(FullName) = chop4(FullName)[strstrt(chop4(FullName),'\')+1:*]
chop6(FullName) = chop5(FullName)[strstrt(chop5(FullName),'\')+1:*]
chop(FullName) = chop6(FullName)[strstrt(chop6(FullName),'\')+1:*]

FileName = chop(TestFile)
print FileName

If anybody knows a more elegant or smarter solution, please let me know.