Re: [Gnuplot-info] re ad a datafile into an array, is it possible?

[Thomas S. <t.s...@fz...>]

use 'columnstring(0)'
note: numbering of read in data lines starts with 0
(have a look at 'pseudocolumns' in the manual)


bsmile wrote:
> 
> Thanks, Thomas, very enlightening! Basically you created a string which
> contains the characters forming the commands to create all the variables,
> then run the string as a macro.
> 
> A bit further question, what if the data file does not have the first
> column, say bbb.txt
> 
> 0.56
> 0.45
> 0.56
> 0.65
> 
> and I still want to read these variables into an array
> 
> v1 = 0.56
> v2 = 0.45
> v3 = 0.56
> v4 = 0.65
> 
> if still follow your logic, I don't have a columnstring(?) to give 1,2,3,4
> ..., then what should I do?
> 
> Thanks again,
> 
> Sincerely,
> Jon
> 
> 
> 
> On Mon, Jan 31, 2011 at 3:33 AM, Thomas Sefzick
> <t.s...@fz...>wrote:
> 
>>
>> try this:
>>
>> set macro
>> set term dumb
>> vs=""
>> ws=""
>> plot 'aaa.txt' using ( \
>>   vs=vs.'; v'.stringcolumn(1).'='.stringcolumn(1), \
>>   ws=ws.'; w'.stringcolumn(1).'='.stringcolumn(2), \
>>   $1):2
>> print "vs: |".vs."|"
>> print "ws: |".ws."|"
>> @vs
>> @ws
>> show var
>>
>>
>> bsmile wrote:
>> >
>> > Dear All,
>> >
>> > I just asked something about mathematical operation, and Thomas gave me
>> > very
>> > useful hint. So let me ask something more advanced in my point of view.
>> Is
>> > it possible to define an array in gnuplot, and read each row of a file
>> > into
>> > the array, for example,
>> >
>> > 1  0.56
>> > 2  0.45
>> > 3  0.56
>> > 4  0.65
>> >
>> > ?
>> >
>> >>From what I know, I would think of the following
>> >
>> > p 'aaa.txt' u ( 'v'.$1=$1, 'w'.$1=$1 ):2
>> >
>> > and it seems that
>> >
>> > v1=1, w1=0.56
>> > v2=2, w2=0.45
>> > ...
>> >
>> > But if I run the code, it fails, complaining that ')' expected
>> >
>> > Any suggestions?
>> >
>> > Thanks,
>> >
>> > Sincerely,
>> > Jon
>> >
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