Re: [Gnuplot-info] re ad a datafile into an array, is it possible?

[Jon <dev...@gm...>]

Thanks, Thomas, very enlightening! Basically you created a string which
contains the characters forming the commands to create all the variables,
then run the string as a macro.

A bit further question, what if the data file does not have the first
column, say bbb.txt

0.56
0.45
0.56
0.65

and I still want to read these variables into an array

v1 = 0.56
v2 = 0.45
v3 = 0.56
v4 = 0.65

if still follow your logic, I don't have a columnstring(?) to give 1,2,3,4
..., then what should I do?

Thanks again,

Sincerely,
Jon



On Mon, Jan 31, 2011 at 3:33 AM, Thomas Sefzick <t.s...@fz...>wrote:

>
> try this:
>
> set macro
> set term dumb
> vs=""
> ws=""
> plot 'aaa.txt' using ( \
>   vs=vs.'; v'.stringcolumn(1).'='.stringcolumn(1), \
>   ws=ws.'; w'.stringcolumn(1).'='.stringcolumn(2), \
>   $1):2
> print "vs: |".vs."|"
> print "ws: |".ws."|"
> @vs
> @ws
> show var
>
>
> bsmile wrote:
> >
> > Dear All,
> >
> > I just asked something about mathematical operation, and Thomas gave me
> > very
> > useful hint. So let me ask something more advanced in my point of view.
> Is
> > it possible to define an array in gnuplot, and read each row of a file
> > into
> > the array, for example,
> >
> > 1  0.56
> > 2  0.45
> > 3  0.56
> > 4  0.65
> >
> > ?
> >
> >>From what I know, I would think of the following
> >
> > p 'aaa.txt' u ( 'v'.$1=$1, 'w'.$1=$1 ):2
> >
> > and it seems that
> >
> > v1=1, w1=0.56
> > v2=2, w2=0.45
> > ...
> >
> > But if I run the code, it fails, complaining that ')' expected
> >
> > Any suggestions?
> >
> > Thanks,
> >
> > Sincerely,
> > Jon
> >
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