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From: Thomas S. <t.s...@fz...> - 2009-12-04 18:22:10
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the formula for differential cross section of rutherford scattering is dsigma/dOmega ~ 1/(sin(theta/2)**4) this function can not have the shape you've drawn in your graph. it *is* infinite at x=0. the reason not to take the data point at x=0 into account, is that all non-scattered particles go under zero degree, but you are interested in scattered particles only, i.e. those particles which are described by the above formula. i don't see anything wrong with your data and your fit as it is. Hans-Bernhard Bröker-2 wrote: > > DonBieber wrote: > >> I have data concerning rutherford-scattering. In order to verify the >> formula >> I need to make a fit with the function f(x)=a*1/(sin(x/2)**4). Like you >> can >> see I get for x=0 a little mathematical problem. The following picture >> shows >> the fit in green and how I would like it to be in blue. Is there any >> possibility of telling GnuPlot to skip x=0 and interpolate? > > Throw away the data point at x=0 (and all other exact multiples of \pi, > of course) before you pass the data to the 'fit' command. > > > > ------------------------------------------------------------------------------ > Join us December 9, 2009 for the Red Hat Virtual Experience, > a free event focused on virtualization and cloud computing. > Attend in-depth sessions from your desk. Your couch. Anywhere. > http://p.sf.net/sfu/redhat-sfdev2dev > _______________________________________________ > Gnuplot-info mailing list > Gnu...@li... > https://lists.sourceforge.net/lists/listinfo/gnuplot-info > > -- View this message in context: http://old.nabble.com/Problem-with-singularity-%3C-%3E-Divide-by-zero-tp26634110p26636364.html Sent from the Gnuplot - User mailing list archive at Nabble.com. |