Re: Gnuplot time is 5 hours ahead of the rest of the world

[<pl...@pi...>]

On Wed, 08 Aug 2007 11:52:33 +0200, Hans-Bernhard Bröker  
<HBB...@t-...> wrote:

> That's the mean number of seconds of the actual astronomical year.  But
> we're dealing with calendars here, not with astronomy.  The average
> length of a calender year, in the period under consideration (1970 to
> roughly 2038), is 365.25 days.  Multiply that by DAY_SEC and you get
> exactly those 31557600 seconds found in our YEAR_SEC.

That's the average over a period with exactly 3 non leap years and one  
leap year. This will not be the average of any arbitary period within the  
range you indicate.

What is required is the actual number of leap and non leap years an thier  
actual number of days 365/366, not an average ( I presume you are in fact  
refering to the mean rather than "average" which has several definitions).

Applying an average here is like expecting the family next door to have  
2.4 children. ;)