Re: tiny fonts with wxt term

[Daniel J S. <dan...@ie...>]

Daniel J Sebald wrote:
> Richard Henwood wrote:
> 
> 
>>Anyway... here you go:
>>
>>http://www2.warwick.ac.uk/cll/skills/eportfolio/students/eportfoliodirectory/current/phrfaj/gnuplotproblems/gnuplotfontproblem2.png
> 
> 
> Furthermore, there is something interesting about the polygon
> compared to what I see in the x11 "test".  In your screenshot
> the polygon looks nice and symmetric.  In the x11 test on my
> screen (see below) I'm seeing an asymmetric polygon.  The
> aspect ration for the two screen shots is about the same.
> I can understand that the lines might be a different thickness
> and that sort of thing.  But why should the aspect ration of
> the polygon be so different?

This seems to be an issue with x11 dimensions.  (Guess I recall this now.)  test_term() assumes the ratio is 1:1 by virtue of

            for (i = 0; i < n; i++) {
                corners[i].x = cen_x + radius * cos(2*M_PI*i/n);
                corners[i].y = cen_y + radius * sin(2*M_PI*i/n);
            }

There is no attempt to make the polygon appear symmetric.  Of course, the formula could be appropriately scaled to attempt a symmetric hexagon, but even that won't work so well.  For the x11 terminal, t->xmax and t->ymax are fixed at 4096 in x11.trm.

The ramifications of that are not that important right now, but I do wonder why if x11.trm assumes 4096 by 4096 the default window size in gnuplot_x11 is

static unsigned int gW = 640, gH = 450;

You'd think a logical choice would be to make the ratio t->xmax : t->ymax the same as the ratio gW : gH.  (I know, just change .geometry in the X resources.)

As a simple test, I've changed 

# define X11_YMAX 4096

to

# define X11_YMAX 2880

inside x11.trm.  Then in gplt_x11.c I've gone through and modified all the spots where a 4096 should be 2880 and 4095 should be a 2879 to get the plot aligned correctly.  (These numbers should be derived from a #define value.)

Below is the before and after screen shot for a non-resized x11 window.

Dan