Re: [Sdcc-user] unsigned char to unsigned int warning

[Jesus Calvino-F. <Je...@ec...>]

Hi Daryl,

This looks incorrect to me:

uchar A;
.
.
.
A="Hello ";

You are assigning a pointer to string to a char (I am assuming that 
"#define uchar unsigned char" is someplace in the file).  Instead, it 
should look like:

uchar * A;
.
.
.
A="Hello ";
ptrA=A; //A is already a pointer so no '&'


Jesus

At 08:31 PM 12/4/02 -0600, Daryl Gallatin wrote:
>Hi,
>I'm trying to compile a c program that will display a text string to an 
>LCD display. I know I have to use a pointer which I am doing, but it 
>doesn't work. I get a wierd warning that doesn't make sense to me
>
>lcddisplay.c(41):warning *** indirections to different types assignements 
>type --> 'array of const char' assigned to type --> 'unsigned int'
>
>I can still compile the program but it doesn't.
>If I do a simple program for dos that uses pointers, I can get it to 
>display the text
>
>my program declarations are
>
>void main(void)
>         {
>         uchar A;        //declare an unsigned character varible
>         int count;
>         unsigned char *ptrA;   //declare a pointer
>
>
>
>         count=0;
>         A="Hello ";
>    ptrA=&A;  //Pointer ptrA points to the address location of the first 
> character of variable A
>
>The ptrA=&A is line 41. How is this an unsigned int?
>...
>
>for(count=0;count<5;count++)
>                 {
>                 LCDputchar(*ptrA);   // Display the letter that the 
> pointer ptrA points to
>                 ptrA=ptrA+1; //increment the address that pointer ptrA 
> points to by 1
>                 }
>
>
>
>void LCDputchar(uchar value)
>         {
>         int i;
>         P2=value;
>         ENABLE=1;
>         for(i=0;i<125;i++);     //delay
>         ENABLE=0;
>         }
>
>
>I can do an equivalent DOS program that works fine.
>Thanks for any help
>
>DAryl
>
>
>
>
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