[Maxima-bugs] [ maxima-Bugs-1430843 ] integrate(x/(1-x^2), x) and integrate(x/(x^2-1), x)

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Bugs item #1430843, was opened at 2006-02-13 13:10
Message generated for change (Comment added) made by dgildea
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Category: Lisp Core - Integration
Group: None
Status: Open
Resolution: None
Priority: 5
Private: No
Submitted By: Raymond Toy (rtoy)
Assigned to: Nobody/Anonymous (nobody)
Summary: integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x)

Initial Comment:
integrate(x/(1-x^2),x) and integrate(x/(x^2-1),x) don't
ask if x < 1 or x > 1.  Because of this we get two
different results, when they should be equivalent,
depending on the range of integration.


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>Comment By: Dan Gildea (dgildea)
Date: 2011-01-24 16:25

Message:
(%i2) integrate(x/(1-x^2),x);
(%o2) -log(1-x^2)/2
(%i3) integrate(x/(x^2-1),x);
(%o3) log(x^2-1)/2

The two results are equivalent except for their sign, and a constant term
of log(-1).
I don't understand the problem.



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