Re: [Libmesh-users] can VISIT show deformed shape in problem of elasticity?

[Derek G. <fri...@gm...>]

BTW - this is pretty easy with Paraview.  Just name your displacements
disp_x disp_y and disp_z  ... and then when you load the result click the
little checkbox next to "Apply Displacements".  The box with the "1" in it
right next to that checkbox allows you to "exaggerate" the displacements if
you wish.

Derek

On Tue, Sep 25, 2012 at 9:12 PM, Boyce Griffith <gri...@ci...>wrote:

> On 9/25/12 11:01 PM, walter kou wrote:
> > I just use VISIT 2.5.2 to visualize the output data in example: 3D Linear
> > Elastic Cantilever
> > ,<http://libmesh.sourceforge.net/systems_of_equations_ex6.php>
> > I can see the displacement and force drawn on initial configuration. But
> I
> > wonder whether I can see the deformed configuration in VISIT. (I want to
> > see how the beam bends)
>
> It takes a little work to do this in VisIt, but it can be done.  Setup a
> new "vector" expression whose components are the scalar components of
> the displacement vector.  E.g. if the displacement vector has components
> u1, u2, u3, then I would set up an expression named "u" that is defined by:
>
>     {u1,u2,u3}
>
> Next, use the deform operator to deform the mesh or other plots.  You
> will need to set the operator attributes for the deform operator to
> correspond to the displacement vector.
>
> You may want to save settings after doing this so that VisIt remembers
> the definitions of the expressions.
>
> -- Boyce
>
> PS: By default, when you have libMesh output an ExodusII file of a 2D
> mesh, the generated file actually contains a 3D mesh, but with the z
> component set to zero.  So if you try to do this with a 2D simulation,
> you would use:
>
>     {u1,u2,0}
>
> and not:
>
>     {u1,u2}
>
> In this case, you might also want to use the "project" operator.  (Also,
> I think you still need to give all three components even if you first
> apply the project operator.)
>
>
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