Re: [uml-user] X-compiling modules for UML

[Adrian P. <a.p...@dn...>]

>>>>> "Gabriel" == Gabriel Paues <ga...@si...> writes:

    Gabriel> Hi!  I'm developing a new kernel module and want to try
    Gabriel> it with UML. I use the rh7.2-rootfs and my host is
    Gabriel> running the same dist as well. I use the following
    Gabriel> Makefile:

    Gabriel> #Makefile CC=gcc MODCFLAGS := -Wall -DMODULE -D__KERNEL__
    Gabriel> -DLINUX

    Gabriel> ip6headsniff.o: ip6headsniff.c
    Gabriel> /usr/include/linux/version.h $(CC) $(MODCFLAGS) -c
    Gabriel> ip6headsniff.c

    Gabriel> When I compile it, my module (naturaly) gets its version
    Gabriel> from /usr/include/linux/version.h and uses all standard
    Gabriel> includes (from Red Hat 7.2). That means it gets compiled
    Gabriel> for kernel 2.4.7-10. It does also mean that I cannot
    Gabriel> insmod it into my UML-kernel since it is running
    Gabriel> 2.4.13um.

    Gabriel> What I want is crosscompile the module. Since the
    Gabriel> /usr/include/linux directory is from kernel version
    Gabriel> 2.4.17-10 in the root_fs i cannot compile the module on
    Gabriel> the UML natively either.

    Gabriel> What is the trick? I suppose there is because this must
    Gabriel> be the primary use of UML after all... :-)

If you're compiling a kernel module then you have to compile against
the version you wish to load it in. Don't use /usr/include/linux has
these headers are for glibc's use. You'll need a -I<path to kernel
headers> in your makefile and you can drop the explicit version.h,

Sincerely,

Adrian Phillips

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