Re: [Swig-user] C++: Equivalent types?

[William S F. <ws...@fu...>]

If I use the code below, I can't see any difference in the marshalling 
for the two strings in the foo method. What differences do you see?

%include <std_string.i>
%include <std_vector.i>
%define SWIG_TYPECHECK_SSTRING        250    %enddef
%typemaps_std_string(synthesis_common::SString, char, SWIG_AsCharPtrAndSize,
                      SWIG_FromCharPtrAndSize, %checkcode(SSTRING));

%template(SStringVector)    std::vector<synthesis_common::SString>;
%template(StringVector)     std::vector<std::string>;

%inline %{
void foo(std::vector<synthesis_common::SString> sstring, 
std::vector<std::string> stdstring) {
}
%}

William

Craig Files wrote:
> Yes, I did see your posting. (I am using ruby.)
> 
> When I tried the %apply, it do not work unless I used the typemap from
> std_string.i, but if I use the typemap, then the generated C file is the same
> with or without the %apply.
> 
> The funny thing is that using (taken from typemaps/std_string.swg)
> %typemaps_std_string(synthesis_common::SString, char, SWIG_AsCharPtrAndSize,
>                      SWIG_FromCharPtrAndSize, %checkcode(SSTRING));
> 
> 
> Generates correct in--outs for the methods.  But, again the vectors are not
> the same, i.e....
> 
> %template(SStringVector)    std::vector<synthesis_common::SString>;
> %template(StringVector)     std::vector<string>;
> 
> Don't generate the same way.
> 
> 
> 
> On Fri, Apr 17, 2009 at 3:57 AM, William S Fulton
> <ws...@fu...> wrote:
>> Craig Files wrote:
>>> Murray,
>>>
>>> Â I was looking through the swig mailing list and found your post, and
>>> am curious if you found a solution?
>>>
>> Did you see my posting on 13 April?
>>
>> William
>>
>>
>