[Oorexx-bugs] [ oorexx-Bugs-2048379 ] syntax parsing error

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Bugs item #2048379, was opened at 2008-08-12 14:59
Message generated for change (Comment added) made by wb4alm
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Category: Interpreter
Group: None
Status: Closed
Resolution: Invalid
Priority: 5
Private: No
Submitted By: W.W. Turner III  (Bill) (wb4alm)
Assigned to: Nobody/Anonymous (nobody)
Summary: syntax parsing error

Initial Comment:

The statement

say "    step2c: if ("((leftdigit%2)*2)") =" leftdigit

results in an error message: 

REX0043E: Error 43 running /home/bill/RexxProduction/ABA/evenodd.rex line 74:  Routine not found

REX0417E: Error 43.1:  Could not find routine "    step2c: if ("

which should not have been issued because the  "IF (" is inside a quoted literal.

if, however, you place a blank after the second (") quote mark and also before the Third quote. the statement
will be processed correctly.

See additional notes inside the attached example program.

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>Comment By: W.W. Turner III  (Bill) (wb4alm)
Date: 2008-08-12 20:44

Message:
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The intent was that the " was the end of the literal
and I have not had to use the explicit || before...

I frequently place a say in front of a working statement
and add a few quotes to produce "debugging" statements 
(less output then the builtin trace system.)

and I was not aware of " the Literal string immediately
followed by a ( " being treated as a function call.



Do you remember when this became part of the overall REXX spec and what
the intent was?
or is this fallout caused by the internal conversion of "classic style" to
an "oo style"?

All of my early books on rexx are packed away, so I can't look it up.

I can see where   abc(   would be treated as a function call,
but I'm not sure  why   'abc'(   would be treated that way too.

in my way of thinking    def = 'abc'(xyz%2)*2)
should result in def being assigned the value 'ABC' followed by a number
using implied concatenation rules.

Just curious and always learning <grin>


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Comment By: Rick McGuire (bigrixx)
Date: 2008-08-12 15:12

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This IS getting parsed correctly.  Your literal string has embedded "
characters within it, which terminate that literal.  You need to double up
the embedded literals or use the alternate ' form to get this to work.  

say " step2c: if (""((leftdigit%2)*2)"") =" leftdigit

or 

say " step2c: if ('((leftdigit%2)*2)') =" leftdigit

Or, if you really intended that " to be the end of the literal portion,
then you need to use the explicit || 
operator to perform the concatenation because a literal string immediately
followed by a ( is interpreted as a function call....which would give
precisely the error you received. 

say " step2c: if ("||((leftdigit%2)*2)") =" leftdigit

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