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From: 孔涛 <ka...@ye...> - 2014-08-23 02:32:24
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Hi, everyone. How to print fortran allocatable array in GDB? For example, the source file reads -- program main implicit none real,dimension(5) :: a real,dimension(:),allocatable :: b allocate(b(10) ) call random_number(a) call random_number(b) deallocate(b) end program -- I use 'gfortran -g arr.f90 ' and use 'gdb ./a.exe' Then I got the following debug info --------------------------------- (gdb) b 6 (gdb) b 10 (gdb) r Starting program: D:\Documents\Projects\test/a.exe [New Thread 6844.0x1a40] Breakpoint 1, MAIN__ () at array.f90:6 6 allocate(b(10) ) (gdb) p a $8 = (3.76478451e-039, 1.54142831e-044, 1.03794626e-038, -nan(0x7ffffe), 0) (gdb) p b $9 = (0) (gdb) c Continuing. Breakpoint 2, MAIN__ () at array.f90:11 11 deallocate(b) (gdb) p a $10 = (0.997559547, 0.566824675, 0.965915322, 0.747927666, 0.367390871) (gdb) p b $11 = (0) (gdb) ---------------------------------------- So why? How to show the variable b? -- Have a nice day! Kayneo ---- I saw, I came, I conquered! |