#509 C99 'z' format modifier not implemented correctly

[Jason Schulz]

The C99 'z' format modifier does not appear to be implemented correctly.

A simple example to demonstrate...

#include <stdio.h>

int main(const int argc, const char* argv[]) {

  printf("%zu\n", (size_t) -1);

  return 0;
}

The expected would normally be,

18446744073709551615

for Windows 64bit.

The actual output is,

zu

[Kai Tietz]

Hi Jason,

the behavior you see here is absolutely that one to be expected. By default mingw-w64's crt-headers are providing MS' variant of printf/scanf routines, which are indeed no compliant to gnu-ish variant you are testing here.

Nevertheless mingw-w64 provide a way to make use of the gnu-ish C99 printf/scanf routines, You either have to include libstdc++'s config-header (or one of its STL headers) it provides, or to make sure that the macro '__USE_MINGW_ANSI_STDIO' is defined with value '1' (please before including any c-runtime headers).

Hope this helps. I close this bug as works for me.