Re[2]: [Matplotlib-users] compresson ratio

[Alan G I. <ai...@am...>]

On Tue, 14 Sep 2004, John Hunter apparently wrote:
>     def square():
>         fig = gcf()
>         ax = gca()
>         figw, figh = fig.get_size_inches()
>         l,b,axw,axh = ax.get_position()

>         side = min([figw, figh])
>         frac = min([axw, axh])

>         fig.set_figsize_inches(side, side)
>         ax.set_position([l,b,frac,frac])
>         axis('equal')
>         draw()


OK, this does not work for me.
Test case:
d=arange(201)*pi/100
plot(cos(d),sin(d))
square()
show()
This should look like a circle.
It looks like an oval.

Problems:
1. fig.set_figsize_inches is ignored.
It has no effect on figure size.
(It changes the size the figure reports,
as checked by printing it, but not the
size that is drawn---a missing argument
to draw?)
2. axis('equal') should not be desirable,
if it is matlab compatible
 http://www.mathworks.com/access/helpdesk/help/techdoc/ref/axis.html 
That is, square() should set an axis aspect ratio of unity,
but axis('equal') should equate the *unit length* along each
axis.  (For my example circle this is not a problem, but in
generaly this is completely wrong.)

Hope that's useful,
Alan Isaac