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From: John H. <jdh...@ac...> - 2003-12-15 14:16:56
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>>>>> "K" == K KISHIMOTO <ko...@us...> writes:
K> I am sorry that my last explanation was insufficient. The
K> point is that I think it is inefficient to execute the
K> following two lines in matplotlib.mlab.hist when I know the
K> result of "n" already.
Good point ...
K> Another point is hist() does not support error bar plot (but
K> bar() called from hist() does support.)
Another good point....
K> So, I propose again def hist(x, bins=10, noplot=0, normed=0,
K> weights=None, errors=None , **kwargs): in matplotlib.matplab.
K> I think if matplotlib supports this by default, it is very
K> smart and usefull to many users when making histogram plots
K> with matplotlib than letting hist() be mainly for the purpose
K> of "calculating" histograms.
OK, I'll give it some thought. Sounds reasonable enough. It doesn't
break backwards compatibility, adds useful features, and is more
consistent with bar.
JDH
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