Re: [Matplotlib-users] sharex with one figure aspect = 1.0

[Thomas C. <tca...@gm...>]

Can you please provide a minimal, but complete and runnable example of what
you are doing?

On Wed, Apr 8, 2015, 08:13 Mark Bakker <ma...@gm...> wrote:

> Thanks, Thomas.
>
> That works indeed, but it doesn't make the figure adjustable, which is
> what I wanted (that the physical size of the axes changes while the aspect
> ratio is fixed to 1). I guess that functionality has been taken out.
>
> Mark
>
> On Wed, Apr 8, 2015 at 12:50 PM, Thomas Caswell <tca...@gm...>
> wrote:
>
>> What are the data limits you are using?
>>
>> I suspect they you are over constraining the system/order of operations
>> issue. Try dropping the adjustable setting and pre setting both the data
>> limits and the approximate size in figure fraction (ex via grid spec) of
>> the axes.
>>
>> Tom
>>
>> On Tue, Apr 7, 2015, 15:54 Mark Bakker <ma...@gm...> wrote:
>>
>>> Hello list,
>>>
>>> I want to axes above each other. They share the x-axis. The top figure
>>> has 'aspect=1' (it is a map), the bottom figure shows a cross-section along
>>> a horizontal line on the map, so it doesn't have 'aspect=1'. When I do this
>>> with code, for example like this:
>>>
>>> fig, axes = plt.subplots(nrows=2,sharex=True)
>>> plt.setp(axes[0], aspect=1.0, adjustable='box-forced')
>>>
>>> then the physical size of the top axes is much sorter than the physical
>>> size of the bottom axes (although they are poperly linked, as they have the
>>> same data limit, and when zooming in the top figure, the bottom figure
>>> adjusts). It just looks weird, as the size of the horizontal axis of the
>>> bottom figure should have the same physical size as the horizontal axis of
>>> the top figure. This used to be possible (a few years ago; haven't tried it
>>> for a while). Is there a way to do it with the current matpotlib? (1.4.3)
>>>
>>> Thanks,
>>>
>>> Mark
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>>
>