Re: [Matplotlib-users] Set a 3-D point?

[Prahas D. N. <pra...@gm...>]

Hi,

For those of you following the trials and tribulations of moi,
I hacked the solution.  The assignment is:

x0 = [ [-1.0,0.0,0.5] ]

I printed the orig x0.  Printed mine.  Noticed mine was missing
a set of brackets.  Tried it.  Success!

--Prahas




On Sun, Mar 29, 2015 at 10:07 AM, Prahas David Nafissian <
pra...@gm...> wrote:

>
> Hi Mat-Plotters,
>
> I'm trying to modify the below code so that I can
> set the initial conditions to (-1,0,0.5).
>
> The code below randomly sets the initial conditions:
>
> **************
>
> # I changed the equation -- it's not Lorenz.
>
> N_trajectories = 1
>
> def lorentz_deriv((x, y, z), t0, aa=1.1, yy=0.87):
>     """Compute the time-derivative of a Lorentz system."""
>     return [y*(z-1+x*x)+yy*x, x*(3*z+1-x*x)+yy*y, -2*z*(aa+x*y)]
>
> # Choose random starting points, uniformly distributed from -15 to 15
>
> np.random.seed(1)
>
> *# Here's the statement which assigns the initial conditions:*
>
> x0 = -15 + 30 * np.random.random((N_trajectories, 3))
>
> ******************
>
> I tried simply doing this:
>
> x0 = (-1,0,0.5)
>
> but I get this error:
>
> ValueError: need more than 1 value to unpack
>
>
> What am I missing?  What is the correct way to make the assignment?
>
>
> Thanks!
>
>
> --Prahas
>
>
>
>
>