Re: [Matplotlib-users] Best way to display image from URL in Python3

[Ryan N. <rne...@gm...>]

Thomas, sorry I missed your email.

I'll see if I can get a PR pulled together soon-ish.

Ryan

On Fri, Mar 20, 2015 at 4:32 PM, Ryan Nelson <rne...@gm...> wrote:

> A little update. It seems that this seems to be specific to Linux in some
> way. I tried the original script from the PR under a couple of conditions:
> * on Windows 7 Anaconda Python 2.7 and 3.4 -- everything works both
> versions
> * on Anaconda Python 2.7 and 3.4 Linux version -- only the 2.7 version
> works
> * on Gentoo Linux Python 2.7 and 3.4, MPL 1.4.3 -- only the 2.7 version
> works
> Hope that helps.
>
> Ryan
>
> On Fri, Mar 20, 2015 at 3:41 PM, Jerzy Karczmarczuk <
> jer...@un...> wrote:
>
>>
>> Le 20/03/2015 16:57, Ryan Nelson a écrit :
>> > For me, if I change the script from the PR to what is shown below,
>> > everything works fine in both Python 2.7 and 3.4 (Anaconda
>> > environments, everything updated):
>> > ##################
>> > url = 'http://www.libpng.org/pub/png/img_png/pngnow.png'
>> > try:
>> >     import urllib2
>> >     data = urllib2.urlopen(url)
>> > except Exception:
>> >     import urllib.request
>> >     from io import BytesIO
>> >     data = BytesIO(urllib.request.urlopen(url).read())
>> >
>> > from matplotlib import pyplot
>> >
>> > image = pyplot.imread(data)  # crash on py3.x
>> > pyplot.imshow(image)
>> > pyplot.show()
>> > #################
>> > But as you can see, the Python 3 version requires the addition of
>> > BytesIO and read(). I take it that this is not supposed to be the case.
>>
>> It works for X.png, not for X.jpg. The call of imread() fails then.
>> Tested also under 3.4/Anaconda.
>>
>> Jerzy Karczmarczuk
>>
>>
>>
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