Re: [Matplotlib-users] Best way to display image from URL in Python3

[Jerzy K. <jer...@un...>]

Le 20/03/2015 16:57, Ryan Nelson a écrit :
> For me, if I change the script from the PR to what is shown below, 
> everything works fine in both Python 2.7 and 3.4 (Anaconda 
> environments, everything updated):
> ##################
> url = 'http://www.libpng.org/pub/png/img_png/pngnow.png'
> try:
>     import urllib2
>     data = urllib2.urlopen(url)
> except Exception:
>     import urllib.request
>     from io import BytesIO
>     data = BytesIO(urllib.request.urlopen(url).read())
>
> from matplotlib import pyplot
>
> image = pyplot.imread(data)  # crash on py3.x
> pyplot.imshow(image)
> pyplot.show()
> #################
> But as you can see, the Python 3 version requires the addition of 
> BytesIO and read(). I take it that this is not supposed to be the case.

It works for X.png, not for X.jpg. The call of imread() fails then. 
Tested also under 3.4/Anaconda.

Jerzy Karczmarczuk