|
From: Benjamin R. <ben...@ou...> - 2015-03-20 13:51:37
|
According to the PR you reference, the fix for this was merged back in Jan 2013, so that means that this fix is in version 1.2.x and up. Are you saying that you still can't do imread(urllib.request.urlopen(url))? On Thu, Mar 19, 2015 at 8:54 PM, Ryan Nelson <rne...@gm...> wrote: > Hello all, > > I'm porting over some code that used Py2.7 urllib2.urlopen(url) to grab > some image data from the net and load with pyplot.imread. It doesn't work > quite right in Py3.4. I found a couple of refs: > > https://github.com/matplotlib/matplotlib/pull/1650 > > http://stackoverflow.com/questions/15183170/python-crash-when-downloading-image-as-numpy-array > > They suggest io.BytesIO(urllib.request.urlopen(url).read()) as a > replacement for Py3. Is this the best practice? Does anyone know a simpler > way to do this? > > Ryan > > > ------------------------------------------------------------------------------ > Dive into the World of Parallel Programming The Go Parallel Website, > sponsored > by Intel and developed in partnership with Slashdot Media, is your hub for > all > things parallel software development, from weekly thought leadership blogs > to > news, videos, case studies, tutorials and more. Take a look and join the > conversation now. http://goparallel.sourceforge.net/ > _______________________________________________ > Matplotlib-users mailing list > Mat...@li... > https://lists.sourceforge.net/lists/listinfo/matplotlib-users > > |