Re: [Matplotlib-users] ValueError: x and y must have same first dimension

[surfcast23 <sur...@gm...>]

That worked beautifully thank you!
Am I reading  (bins[1]-bins[0]) correctly as taking the difference between
what is in the second and first bin?



Daπid wrote:
> 
> I guess it is showing, but you have many data points, so the gaussian
> is too small down there. You have to increase its values to make both
> areas fit:
> 
> plt.plot(bins, N* N*(bins[1]-bins[0])**y, 'r--', linewidth=1)
> 
> 
> And you will get a nice gaussian fitting your data.
> 
> On Fri, Jul 27, 2012 at 11:12 PM, surfcast23 <sur...@gm...> wrote:
>>
>> Thanks for catching that sigma was still a vector! I am no longer getting
>> the
>> errors, but the best fit line is not showing up.Is there something else I
>> am
>> missing ?
>> BTW thanks for the heads up on the np.mean and np.standard functions.
>>
>> Khary
>>
>> Daπid wrote:
>>>
>>> On Fri, Jul 27, 2012 at 9:57 PM, surfcast23 <sur...@gm...>
>>> wrote:
>>>> y = mlab.normpdf( nbins, avg, sigma)
>>>> l = plt.plot(nbins, y, 'r--', linewidth=1)
>>>> plt.show()
>>>
>>> You should not change bins there, as you are evaluating the gaussian
>>> function at different values.
>>>
>>> Also, sigma is a vector, but it should be an scalar:
>>>
>>> sigma = np.sqrt((1./len(C))*(diff**2))
>>>
>>> should be
>>>
>>> sigma = np.sum(np.sqrt((1./len(C))*(diff**2)))    # The sum of the
>>> previous
>>>
>>> But, much better, you can change the three lines of code by:
>>>
>>> avg=np.mean(C)
>>> sigma=np.std(C)
>>>
>>> They are way faster and more numerically accurate and stable.
>>>
>>>
>>> As a rule of thumb, if you want to do something simple, think that
>>> there should be an easy way of doing it. And if it is something people
>>> do every day (like taking the mean or the std of a vector, or loading
>>> from a txt file), there should be a very easy way of doing it. :-) And
>>> it would probably be faster and more flexible than any naive
>>> implementation.
>>>
>>>
>>> Good luck with your galaxies!
>>>
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>>
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