Re: [Matplotlib-users] Define minimum precision for tick labels

[Warren W. <war...@en...>]

On Fri, Aug 19, 2011 at 3:12 AM, André Dankert <and...@go...
> wrote:

> Hi,
>
> I have a minor style problem, but, nevertheless, I can't solve it with
> googles help. I want to have a minimum precision displayed on my ticks, i.e.
> if the ticks are -1,-0.5,0,0.5,1 it should be displayed this way instead of
> -1.0,-0.5,0.0,0.5,1.0. With the tick formatter I can set the tick
> precission, but only for the whole axis (if I set %d for the example, it
> will be -1,0,0,0,1). Also I use MaxNLocator, so I don't predefine the ticks
> (I thought it's more convinient to use this already done procedure instead
> of writing my own), so I'm more flexible, for example when I zoom in, but
> therefore I don't even know, which the maximum precision is.
>
> Possible solutions would be:
> 1. There is a number precision definition (something like %x.xf) which
> produces numbers with minimum precision (again -1.0000 becomes -1 and
> 2.47300 becomes 2.473)
>


Depending on the range of your values, "%g" might do want you want.  E.g.:

-----
from numpy import linspace, sin, pi
from matplotlib.pyplot import plot, show, gca
from matplotlib.ticker import FormatStrFormatter

majorFormatter = FormatStrFormatter('%g')

t = linspace(-1.0,  1.0, 41)
s = sin(2*pi*t)

plot(t,s)

ax = gca()
ax.xaxis.set_major_formatter(majorFormatter)

show()
-----


Warren




> 2. Extract by MaxNLocator defined ticks, edit them accordingly and reassign
> them (which would be still a lot of work)
>
> I even checked for solutions in Latex (because I use Latex string coding),
> but this is even more inflexible, when it comes to numbers. But maybe
> someone knows anything.
>
> Thanks!
>
> Best regards,
> André
>
>
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