Re: [Matplotlib-users] polar() is not equal to ax.plot (where ax is a PolarAxes)?

[Michael D. <md...@st...>]

I'm not able to see a difference between the two methods here:

from pylab import *
import numpy as np

r = np.arange(0, 3.0, 0.01)
theta = 2*np.pi*r
fig = figure()
ax = fig.add_axes([0.1, 0.1, 0.8, 0.8], polar=True)
ax.plot(theta, r)
show()

polar(theta, r)
show()



Can you provide a standalone script that demonstrates the difference?  
What version of matplotlib are you using?

Cheers,
Mike


plaf wrote:
> Hi all,
>
> I have been trying both ways of plotting polar and found that they behave
> differently?
> Is it just me?
>
> I have sets of theta and R to plot, and when I plotted in console using
> polar() it produces different plot (!) than when I used ax.plot() from my
> application. I compared this with the plot produced in Matlab using the same
> sets of data, and found that it looked closer to my plot produced using
> polar().
>
> I am confused :(
>
> Thank you  
>   

-- 
Michael Droettboom
Science Software Branch
Operations and Engineering Division
Space Telescope Science Institute
Operated by AURA for NASA