Re: [Matplotlib-users] Griddata

[green63 <mag...@vo...>]

I ve a problem with the use of griddata.
I have a grid of x,y with value z. the grid have 4500 points
I would like to have a rigular grid of 1500 points.
I try the function zi = griddata(x,y,z,xi,yi)
but I have an error "too many indices". I don't understant why!!!
x,y,z,xi and yi are numpy array with 1 column.
Sorry for my bad english!!

Thanks

Josh Lawrence-2 wrote:
> 
> Greetings all,
> 
> In using the function griddata in mlab.py, I think I have found a bug.  
> The following line in mlab.py errors for me.
> I supply it an xi and yi that have shape (N,1). I have surface data,  
> but I only care about the variation in one direction. In mlab, when it  
> gets to this line (2956 in svn revision 7040):
> 
>           if min(xo[1:]-xo[0:-1]) < 0 or min(yo[1:]-yo[0:-1]) < 0:
>               raise ValueError, 'output grid defined by xi,yi must be  
> monotone increasing'
> 
> the result is an error. That is, I get the following:
> 
>           ValueError: min() arg is an empty sequence
> 
> A couple of things. First, if I make my variation in x to be 2 points  
> (x = 0 for the case I'm interested in--so I just have both values of x  
> be zero), I do not get this error and I believe the result works. So,  
> it seems that there should be some handling of the case that there are  
> only 1 point in either x or y direction.
> 
> Second, is it better to use the builtin python function min, or should  
> numpy.min be used instead?
> 
> Cheers,
> 
> Josh Lawrence
> Ph.D. Student
> Clemson University
> 
> 
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