[Matplotlib-users] quiver questions/issues (bug?)

[Christopher B. <Chr...@no...>]

Hi all,

I've been messing with quiver a bit, and have some confusions:

according to the docs:

"""
units: [‘width’ | ‘height’ | ‘dots’ | ‘inches’ | ‘x’ | ‘y’ ]

         arrow units; the arrow dimensions except for length are in 
multiples of this unit.
"""

and yes, when I change units from 'dots' for 'inched', the length of the 
arrows do indeed change.


"""
angles: [‘uv’ | ‘xy’ | array]
     ... Alternatively, arbitrary angles may be specified as an array of 
values in degrees, CCW from the x-axis.
"""

This crashes for me with:

Traceback (most recent call last):
   File "quiver_test.py", line 72, in <module>
     plt.draw()
   File 
"/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/pyplot.py", 
line 341, in draw
     get_current_fig_manager().canvas.draw()
   File 
"/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/backends/backend_tkagg.py", 
line 215, in draw
     FigureCanvasAgg.draw(self)
   File 
"/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/backends/backend_agg.py", 
line 279, in draw
     self.figure.draw(self.renderer)
   File 
"/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/figure.py", 
line 772, in draw
     for a in self.axes: a.draw(renderer)
   File 
"/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/axes.py", 
line 1601, in draw
     a.draw(renderer)
   File 
"/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/quiver.py", 
line 425, in draw
     verts = self._make_verts(self.U, self.V)
   File 
"/Library/Frameworks/Python.framework/Versions/2.5/lib/python2.5/site-packages/matplotlib/quiver.py", 
line 484, in _make_verts
     theta = ma.asarray(self.angles*np.pi/180.0).filled(0)
TypeError: can't multiply sequence by non-int of type 'float'

I've enclosed a small test script...

Thanks,

-Chris



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Chr...@no...