Re: [Matplotlib-users] polar in a subplot

[Nils W. <nw...@ia...>]

On Tue, 2 Dec 2008 11:14:48 -0600
  "Ryan May" <rm...@gm...> wrote:
> On Tue, Dec 2, 2008 at 11:07 AM, Nils Wagner
> <nw...@ia...>wrote:
> 
>> Hi all,
>>
>>  If I run the attached example I obtain no polar plots, 
>>but a view like
>> plot(t,r_1) - for what reason ?
>>
> 
> You need to specify polar=True to the subplot commands. 
>Try this:
> 
> from pylab import subplot, polar, linspace, show
> from numpy import pi, sin, cos
> t = linspace(0,2*pi,20)
> r_1 = (1+sin(t))
> r_2 = (1+cos(t))
> subplot(211, polar=True)
> polar(t,r_1) #Or can use plot()
> subplot(212, polar=True)
> polar(t,r_2)
> show()
> 
> Ryan
> 
> -- 
> Ryan May
> Graduate Research Assistant
> School of Meteorology
> University of Oklahoma
  
Hi Ryan,

Thank you very much !
It would be nice to have that information in the docstring

subplot(*args, **kwargs)
     Create a subplot command, creating axes with::

       subplot(numRows, numCols, plotNum)

     where *plotNum* = 1 is the first plot number and 
increasing *plotNums*
     fill rows first.  max(*plotNum*) == *numRows* * 
*numCols*


The next inquiry is related to xticks.
I have added

xticks(linspace(0,2*pi,24,endpoint=False))

The difference between consecutive xticks is varying 
between 14 and 16 degrees.

For what reason ?

Nils