[Matplotlib-users] matplotlib numpy version confusion with ipython -pylab

[Andrew C. <ac...@gm...>]

I recently removed my existing numpy and matplotlib installations and
rebuilt from svn, then installed the matplotlib-0.98.0 egg
If I fire up ipython and then get to work everything is ok, but
attempting to start ipython with the -pylab flag results in a numpy
version error message, as shown below.

I thought I'd removed all traces of the older numpy, but apparently
there is a vestige of it somewhere - anyone else get this?

----------------------------------------------------

spinode: ipython
Python 2.5.2 (r252:60911, Feb 22 2008, 07:57:53)
Type "copyright", "credits" or "license" for more information.

IPython 0.8.2 -- An enhanced Interactive Python.
?         -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help      -> Python's own help system.
object?   -> Details about 'object'. ?object also works, ?? prints more.

In [1]: import numpy

In [2]: numpy.version.version
Out[2]: '1.2.0.dev5255'

In [3]: import pylab

In [4]: pylab.plot([0,0.1,0.5])
Out[4]: [<matplotlib.lines.Line2D object at 0x2280a90>]

In [5]: pylab.show()

In [6]: exit()
Do you really want to exit ([y]/n)? y
spinode: ipython -pylab
numpy 1.1 or later is required; you have 1.0.5.dev4897



-------------------------
Andrew Charles
Centre for Australian Weather and Climate,
Australian Bureau of Meteorology.