Re: [Jython-users] How do I process a shell command and grab stdoutfortext processing?

[Syver E. <syv...@on...>]

This should be a bit better. I tried first to make a subclass of 
org.python.core.PyFile but I got an error message trying to 
assign the self._process attribute to self. Anyone knows why? I
thought one could assign attributes to subclasses of Java classes, but
then I am pretty new in the jython game.


class _ProcessFile:
    def __init__(self, stream, process, name):
        self._file = org.python.core.PyFile(stream, "'%s'" % name)
        self._process = process

    def __getattr__(self, name):
        return getattr(self._file, name)

    def __repr__(self):
        return `self._file`
        
    def close(self):
        self._file.close()
        return self._process.waitFor() or None

def _startProcess(path):
    r = java.lang.Runtime.getRuntime()
    try:
        p = r.exec(path)
        return p
    except java.io.IOException, exc:
        raise OSError(0, exc.toString())

def popen(path, mode='r'):
    p = _startProcess(path)
    if mode == 'r':
        return _ProcessFile(p.getInputStream(), p, path)
    elif mode == 'w':
        return _ProcessFile(p.getOutputStream(), p, path)
    else:
        raise OSError(0, "Invalid mode", mode)

def popen2(path):
    p = _startProcess(path)
    return (_ProcessFile(p.getInputStream(), p, path),
            _ProcessFile(p.getOutputStream(), p,path))

def popen3(path):
    p = _startProcess(path)
    return (_ProcessFile(p.getInputStream(), p, path),
            _ProcessFile(p.getOutputStream(),p, path),
            _ProcessFile(p.getErrorStream(), p, path))


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Vennlig hilsen 

Syver Enstad