Re: [Jython-dev] tomcat4 et PyServlet

[James C. <jc...@in...>]

You have an extra ">" in the web.xml file. It should be okay if you=20
remove it.

James


Thierry Nodenot wrote:

> I've read different messages (see=20
> http://aspn.activestate.com/ASPN/Python/Cookbook/Recipe/54158 and the=20
> available information for installing the Servlet) but I've still=20
> problems to use Servlets in Python with Tomcat4
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> I'am able to run servlets in Java ; Jython is seems to be correctly=20
> configured.
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> The Tomcat Server (version 4) running on a PC (running windows 2000 )=20
> starts without any error but When I load the hello.py=20
> (http://localhost:8080/nods/hello.py), I get this error :
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> description  : The server encountered an internal error (Internal Serve=
r=20
> Error) that prevented it from fulfilling this request.
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> exception=20
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> javax.servlet.ServletException: Wrapper cannot find servlet class=20
> org.python.util.PyServlet> or a class it depends on
>  at org.apache.catalina.core.StandardWrapper.load(StandardWrapper.java:=
807)
>  at=20
> org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:=
615)
>  at=20
> org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperVal=
ve.java:214)
>  at=20
> org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.j=
ava:566)
>  at=20
> org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:=
472)
>  at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:94=
3)
>  at=20
> org.apache.catalina.core.StandardContextValve.invoke(StandardContextVal=
ve.java:201)
>  at=20
> org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.j=
ava:566)
>  at=20
> org.apache.catalina.authenticator.AuthenticatorBase.invoke(Authenticato=
rBase.java:472)
>  at=20
> org.apache.catalina.core.StandardPipeline.invokeNext(StandardPipeline.j=
ava:564)
>  at=20
> org.apache.catalina.core.StandardPipeline.invoke(StandardPipeline.java:=
472)
>  at org.apache.catalina.core.ContainerBase.invoke(ContainerBase.java:94=
3)
>  .......
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> My web.xml file is :
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> <?xml version=3D"1.0" encoding=3D"ISO-8859-1" ?>
>   <!DOCTYPE web-app (View Source for full doctype...)>
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> - <file:///D:/T=E9l=E9chargement/web.xml#> <web-app>
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> - <file:///D:/T=E9l=E9chargement/web.xml#> <servlet>
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>   <servlet-name>pyServlet</servlet-name>
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>   <servlet-class>org.python.util.PyServlet></servlet-class>
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>   </servlet>
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> - <file:///D:/T=E9l=E9chargement/web.xml#> <servlet-mapping>
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>   <servlet-name>pyServlet</servlet-name>
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>   <url-pattern>*.py</url-pattern>
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>   </servlet-mapping>
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>   </web-app>
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> Could you put in the FAQ some instructions to install a Pyservlet examp=
le
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> Where should I put the file : jython.jar  where the PyServlet class is=20
> stored ? It appears that this class in the jython.jar can't be found by=
=20
> the server
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> Thanks for your answer
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> T. NODENOT
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