[Jython-dev] Per Samuele's request - Posted to jython-dev

[Joseph C. <jca...@in...>]

Samuele,
Originally you had:

import org.python.core.*;
import org.python.util.*;

public class Test {

  public static void main(String[] args) {
    PythonInterpreter interp = new PythonInterpreter();
    interp.exec("class A:\n def m(self,a,b):\n  print a,b");
    PyClass A =(PyClass)interp.eval("A");
    PyInstance a = (PyInstance)A.__call__();
    PyObject m = A.__findattr__("m");    
                                                    
    interp.exec("class A:\n def m(self,a,b):\n  print b,a");
    PyClass A2 =(PyClass)interp.eval("A");
    PyInstance a2 = (PyInstance)A2.__call__();
    PyObject m2 = A2.__findattr__("m");        
    
    m2.__call__(a2,new PyInteger(1),new PyInteger(2));
    m.__call__(a,new PyInteger(1),new PyInteger(2)); 
    
  }
}

Which I agree works just fine... however if you modify to look like the 
following:

import org.python.core.*;
import org.python.util.*;

public class Test {

  public static void main(String[] args) {
    PythonInterpreter interp = new PythonInterpreter();
    interp.exec("class A:\n def m(self,a,b):\n  print a,b");
    interp.exec("class B(A):\n def n(self,a,b):\n  print a,b");

    PyClass class =(PyClass)interp.eval("B");
    PyInstance instance = (PyInstance)class.__call__();
    PyObject obj = instance.__findattr__("n");    

// This call works here.                                               
    obj.__call__(instance,new PyInteger(1),new PyInteger(2)); 
         
    interp.exec("class A:\n def m(self,a,b):\n  print a,b");
    interp.exec("class B(A):\n def n(self,a,b):\n  print a,b");

// This call doesn't work here.                                               
    obj.__call__(instance,new PyInteger(1),new PyInteger(2));     
  }
}

You should get the Trace telling you you have to call the unbound method with 
an instance first argument.

-- 
"Every new beginning comes from some other beginnings
end."
        -- Semisonic                 
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