Re: [Jython-dev] jython servlet init() override problem

[<bc...@wo...>]

[Brian Zhou]

>If I write:
>
>def init(self):
>    # do something
>    pass
>
>I got:    TypeError: init() too many arguments; expected 1 got 2
>
>If I write:
>
>def init(self, config):
>    javax.servlet.http.HttpServlet.init(self, config)    # line 14, want
>to do super.init(config) here
>    # do something
>    pass
>
>I got:
>line 14, in init
>TypeError: init() not enough arguments; expected 2 got 1
>
>Am I missing anything?

In java, it is two different methods, but in jython the two methods is
merged into one. In a normal run this method will be called twice, first
with a config param and second (from within GenericServlet.init) without
any parameters.

So the jython method must be prepared to handle both situations:

    def init(self, config=None):
        if config:
            HttpServlet.init(self, config) 
        pass

Obviously jython is completely defeating the purpose of the
parameter-less init() method:

"""
void init() 
    A convenience method which can be overridden so that there's no need
    to call super.init(config).
"""

In jython, we are forced to deal with both init() methods *and* we have
to call super.init() as well.

regards,
finn