Re: [Jetty-support] Force Redirect with Incomplete URL

[Jan B. <ja...@mo...>]

bpratt,

If you're not using a web.xml file to set up security
constraints, then one way to do it would be to change to
using a WebApplicationContext instead of a ServletHandler,
and make a Filter that checks to see if the user is authenticated
and redirects to the Login.html page if not.

Apart from coding your Filter, you'll need to call 
WebApplicationContext.getWebApplicationHandler().defineFilter(name,className) 
and then use one of the WebApplicationHandler.addFilterPathMapping(...)
methods to map your Filter to the urls you want to protect.

regards
Jan
PS Don't forget to upgrade to jetty6! :-)



bpratt wrote:
> Our users must type in the complete path below to get to our welcome page:
> http://localhost:7007/DCConsole/gwt/www/mod/Login.html
> 
> What do I need to add to my code to force a redirect to the welcome page
> (Login.html), if a user types in one of the following:
> 
> http://localhost:7007/DCConsole/
> http://localhost:7007/DCConsole/gwt/
> http://localhost:7007/
> http://localhost:7007/DCConsole/gwt/www/
> 
> Here is my code:
> 
>     SocketListener listener = new SocketListener();
>     listener.setPort(7007);
>     HttpServer fHttpServer.addListener(listener);
>     
>     // create context  
>     HttpContext context = new HttpContext();
>     context.setContextPath("/DCConsole/*");
>     fHttpServer.addContext(context);
>     
>     // create a servlet container
>     ServletHandler servletHandlers = new ServletHandler();
>     servletHandlers.setAutoInitializeServlets(true);
>     context.addHandler(servletHandlers);
>     
>     // map ajax servlet handler onto container 
>     servletHandlers.addServlet("AJAX", "/AJAX/*",
> "com.mycompany.controller.AJAXServlet");
>     
>     // serve static content from the context
>     String home = System.getProperty("jetty.home", ".");
>     context.setResourceBase(home + "/consoles/dcconsole/webapps/");
>     context.addWelcomeFile("Login.html");
>       
>     ...
>     fHttpServer.start();
>     ...
> 
> Thanks in advance!!
> 
> 
> 
>