Re: grid outside border

[Daniel J S. <dan...@ie...>]

Hans-Bernhard Broeker wrote:

>On Mon, 9 Aug 2004, Daniel J Sebald wrote:
>
>  
>
>>Sure, but it would have to be done inside the freqz.m file.  
>>    
>>
>
>I thought that was exactly what I said: that since it's this octave script
>that is deciding that the xrange is going to be [0:1.99805], it's the
>script's job to fix it up.
>
>  
>
>>to recognize that 1023/512 is very close to 2.0.  That is why I suggest 
>>some code somewhere that rounds the borders outward to the nearest, say, 
>>1% of the overall width.  
>>    
>>
>
>If you make "somewhere" be that octave script, I can agree with that.
>
>gnuplot already has such code, but by setting an explicit xrange, the
>script is disabling it.
>

The algorithm I'm describing is probably more difficult than just 
rounding to the nearest 1%, or whatever.  One really wants to round up 
(for right border) to nearest 10^p, 10^p-1, 10^p-2, where p is the 
power, or exponent, associated with right border.

But the point is mute, in this case, because actually, now that I think 
about it, that Octave script is kind of lame.  The sample rate is an 
argument of the freqz() routines.  So why not just set the range to 
[0:Fs/2], rather than reading the maximum range from the frequency 
vector?  I'll send a note to the Octave list.

Dan