Well,
kind' of "did-it-for-you" ... :-)
What about g(x)=a*x/(1.0+b*x)*exp(c*x)
through
fit g(x) "test.dat" via a,b,c
results here in
a=68.4844227089402
b=23.4451718533986
c=-0.0329804676514508
and the fit seems quite acceptable (for me ...)
HTH,
take care
Dieter Jurzitza
On Donnerstag, 2. Januar 2014 23:16:05 smms wrote:
> I know it is rather a "do-it-for-me" post but thought someone could help me
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