#1457 f1(x)=sin(x+pi*(4/3)) isn't plotted correctly

[Oliver]

f1(x)=sin(x+ pi*(4/3))
should be equal and look like:

f2(x)=sin(x+ (pi/3)4)
f3(x)=sin(x+ pi4/3)
f4(x)=sin(x+ pi/34)
f5(x)=sin(x+(pi4)/3))
but isn't.

It looks like that gnuplot ignores the expression "*(4/3)" in f1(x),
because f1(x) is plotted like f6(x)=sin(x+ pi)

This was tested on
G N U P L O T
Version 4.6 patchlevel 4 last modified 2013-10-02
Build System: Linux x86_64
Kubuntu 14.04

[Oliver]

The board software removed the multiplication sign.
I hope this here works now:

    f1(x)=sin(x+pi*(4/3))
    f2(x)=sin(x+ (pi/3) * 4)
    f3(x)=sin(x+ pi * 4/3)
    f4(x)=sin(x+pi / 3 * 4)
    f5(x)=sin(x+(pi * 4)/3)
    f6(x)=sin(x+pi)

[Ethan Merritt]

Gnuplot uses integer arithmetic, so (4/3) evaluates to 1.
Anything times 1 is 1.

You want

f1(x) = sin(x + pi * (4./3.))

[Oliver]

Didn't knew that, sorry and thanks for clarification.