[Gnu-tr-u12a] Re: =?iso-8859-9?q?=5BGnu-tr-u12a=5Dcompiler=2Fassemblers=F6zc=FCkleri=20ve?= =?iso-8859-9?q?s=F6zl=FC=F0=FCkim=FCstlenir=3F?=

[<ni...@fi...>]

sozluk.php =FCzerinde =E7al=FD=FE=FDrken g=F6z=FCmden ka=E7an bir =FEeyle=
r farkettim:

1.----------
> immediate value - =FEimdiki de=F0er

=FEimdiki de=F0er -> current value

immediate value -> =F6rt=FCk de=F0er

olmal=FD san=FDr=FDm.

2.----------
> instruction

Bunun i=E7in y=F6nerge demi=FEtim ama directive i=E7in de y=F6nerge kulla=
nm=FD=FE=FDz.
Biraz ders =E7al=FD=FE=FDnca daha mant=FDkl=FD bir=FEeyler ortaya =E7=FDk=
t=FD gibi...

Statement format:
LABEL FIELD  |  OPERATION FIELD  |  OPERAND FIELD  |  COMMENT FIELD


Label field bir etiketleme alan=FD, ilk sat=FDr de=F0ilse ":" ile bitiyor=
;
operation alan=FDnda ise=20
a symbolic operational code (Instructions Mnemonics)
a directive
a macro call
olabiliyormu=FE. Bunlar=FD =E7evirmedim, =E7=FCnk=FC sorunlu olan bunlar.

Operand alan=FDnda ise i=FElem arg=FCmanlar=FD kullan=FDl=FDyor.

Comment alan=FD ise bildi=F0imiz a=E7=FDklama alan=FD.

=D6rnek:
-----------------
CYCLE	IN	AX,5	;read word from port 5 into AX
	INC	AX	;increment AX
	OUT	2,AX	;write result to port 2
	JMP	CYCLE	;keep repeating
-----------------
Bu durumda

instruction: i=FElem ( IN AX,5 )
operand: terim     ( AX ve 5 )
instruction mnemonic: i=FElem ismi (symbolic names for opcodes) (IN)
directive: y=F6nerge
opcode: i=FElemci kodu (IN AX,5 i=FElemi i=E7in 1110010- gibi bir bitmask=
)

uygun gibi.

Bu hafta i=E7inde ba=FEka =F6neri olmazsa kabul edilmi=FE varsayarak haft=
a sonunda s=F6zl=FC=F0e ekleyece=F0im.

Esen kal=FDn,
Nilg=FCn=20