Re: [Blitz-support] arrays size limit

[Nicolai S. <nic...@gm...>]

Ah and I forgot to explain why there's a std::bad_alloc:

Christopher Subich <cs...@uw...> writes:
> The error you're receiving is thrown by the "new" operator, when the
> memory blob is being created to hold the data, so you would expect to
> see a similar error by calling new_arr = new double[4000000000L].
Basically, the problem is, that 4000000000L overflows an int, which, when
cast to a size_t, is 0xffffffffee6b2800:

Try this:
--8<---------------cut here---------------start------------->8---
#include <cstddef>
#include <iostream>

int
main(int argc, char *argv[])
{
  const int int_size = static_cast<int>(4000000000);
  const size_t size_t_size = static_cast<size_t>(int_size);
  std::cout << "int_size == " << std::hex << int_size
	    << " size_t_size == " << size_t_size << std::endl;
  return 0;
}
--8<---------------cut here---------------end--------------->8---

Now, new[] alway takes a size_t and I'm pretty sure that your machine
doesn't have got a memory size of `0xffffffffee6b2800 * sizeof(double)`
bytes.