Re: [Blitz-support] Structure in a return value

[Marc L. <mar...@gm...>]

Thanks for the info. It would be cool to have the assignment operator
integrated in the library which does the resizing.

Marc

On Wed, Jul 16, 2008 at 5:40 PM, Patrik Jonsson <pa...@uc...> wrote:

> You are assigning the return value of foo() to bla1. Since you haven't
> defined an assignment operator, this uses the default assignment, which does
> not resize the destination. (Assignment is very different from copy
> construction for blitz arrays.) If you compiled with -DBZ_DEBUG, you
> probably get a size mismatch error. If you copy constructed bla1 it should
> work.
>
> (Note however that wrapping the array in a struct like that will prevent
> the expression template machinery from working if you define operators on
> bla.)
>
> cheers,
>
> /Patrik
>
> On 7/16/08, Marc Levesque <mar...@gm...> wrote:
>
>> Hi,
>>
>> I would like to know why in this example the output is not "5":
>>
>> [CODE START]
>> struct bla
>> {
>>   Array<int,1> bou;
>> };
>>
>> bla foo()
>> {
>>   bla bla1;
>>
>>   (bla1.bou).resize(5);
>>
>>   bla1.bou = 4,5,6,7,8;
>>
>>   return bla1;
>> }
>>
>> int main()
>> {
>>   bla bla1;
>>
>>   bla1 = foo();
>>
>>   cout << (bla1.bou).size() << endl;
>>
>>   return 0;
>> }
>> [CODE END]
>>
>> instead the array (bla1.bou) in the main is not initialized, the output of
>> the size shows 0. I've tested it with the <vector> library and it worked.
>> What could be the reason?
>>
>> Thanks a lot
>>
>> Marc
>>
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