From: Young K. <you...@gm...> - 2005-05-16 14:30:35
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Hi, I have studied the UML kernel a bit but it was hard to understand from the code and some document in the web site. I have some questions about the scheduling in UML. so, if anyone answer these, i really appreciate it. Thank you! As long as i know, each process running on top of UML kernel is viewed as a process to the host kernel. then, the host kernel will try to schedule the UML processes as normal processes. well, i'll have an example. suppose there are 2 processes on top of UML and 3 host processes. then, the host kernel sees 5 processes total, so, each of the process will get 20% of the CPU time? is that right? Or, UML is somehow viewed as a group of processes and UML get 25% of the CPU and each UML got 12.5% of the CPU time? if so, how is it possible? one more question, when the UML kernel wants to schedule its processes, how does it preempt UML processes? this way of scheduling and preemption will be different from TT mode and SKAS mode? if so, how? Thank you, |