From: Jim B. <jf...@nf...> - 2003-07-02 23:31:50
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On Wed, 2003-07-02 at 17:30, Asim Shankar wrote: > Hi, > > I'm sorry, I must've misread your earlier statement > > The kernel on the host isn't useless, its just not hte kernel > > that's booting UML. > > What I meant to ask was that the kernel on the root filesystem of the > client, i.e, the vmlinuz-... file on the root filesystem of the client > is useless. Correct? I believe it (the kernel on the root-fs that the UML guest OS is using) is largly unused. It does not represent the kernel you are running in the UML guest. The term 'host' seems to be used for the system running directly on the hardware. When you run './linux udb0=.....' that is often called the guestOS. When you log into the guest after running 'linux' and run 'uname -r' you'll see the version corresponding to that 'linux' executable you are running. |