From: SourceForge.net <no...@so...> - 2006-04-27 14:07:33
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Bugs item #1477696, was opened at 2006-04-27 10:07 Message generated for change (Tracker Item Submitted) made by Item Submitter You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1477696&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core Group: None Status: Open Resolution: None Priority: 5 Submitted By: Raymond Toy (rtoy) Assigned to: Nobody/Anonymous (nobody) Summary: 2*3*2^k is 6*2^k Initial Comment: Current CVS (2006/04/27) has 2*3*2^k becoming 6*2^k. Should this be 3*2^(k+1)? It would be nice, but.... What about a*b^k where a is a large number? Do we want to check if a contains any powers of b so we can return a new result of the form (a/b^k)*b^(k+1)? ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1477696&group_id=4933 |
From: SourceForge.net <no...@so...> - 2006-05-02 17:43:44
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Bugs item #1477696, was opened at 2006-04-27 10:07 Message generated for change (Comment added) made by rtoy You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1477696&group_id=4933 Please note that this message will contain a full copy of the comment thread, including the initial issue submission, for this request, not just the latest update. Category: Lisp Core Group: None >Status: Closed >Resolution: Fixed Priority: 5 Submitted By: Raymond Toy (rtoy) Assigned to: Nobody/Anonymous (nobody) Summary: 2*3*2^k is 6*2^k Initial Comment: Current CVS (2006/04/27) has 2*3*2^k becoming 6*2^k. Should this be 3*2^(k+1)? It would be nice, but.... What about a*b^k where a is a large number? Do we want to check if a contains any powers of b so we can return a new result of the form (a/b^k)*b^(k+1)? ---------------------------------------------------------------------- >Comment By: Raymond Toy (rtoy) Date: 2006-05-02 13:43 Message: Logged In: YES user_id=28849 This particular bug is fixed. We basically handle the case of m/n*b^k and convert that to m1/n1*b^k1 by removing powers of b from m and n. ---------------------------------------------------------------------- You can respond by visiting: https://sourceforge.net/tracker/?func=detail&atid=104933&aid=1477696&group_id=4933 |