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#635 defint(log(1+exp(A+B*cos(phi))),phi,0,%pi) wrong

closed
nobody
5
2008-11-26
2004-10-26
Anonymous
No

Maxima 5.9.0

C1) assume(B>0,B-A>0)$
(C2) integrate(log(1+exp(A+B*cos(phi))),phi,0,%pi);
- B B A
(D2) 3 %PI LOG(%E (%E + %E ))

But if we give A and B numerical values

(C3) B:3$ A:2$ ev(D2,numer);
(C4)
(C5)
(D5) 2.952421848475173
(C6) B:3.2$ A:-3$ ev(D2,numer);
(C7)
(C8)
(D8) .0191075509605848

while by evaluating the integral numerically we obtain
something different

(C11) B:3$ A:2$
romberg(log(1+exp(A+B*cos(phi))),phi,0,%pi);
(C12)
(C13)
(D13) 7.506856487627962
(C14) B:3.2$ A:-3$
romberg(log(1+exp(A+B*cos(phi))),phi,0,%pi);
(C15)
(C16)
(D16) 0.663669430006855

The integrand does not look like the kind of thing that
would give the romberg procedure any trouble

(C25) plot2d(log(1+exp(A+B*cos(phi))),[phi,0,%pi])$

In fact, by visual inspection of the plot it is clear
that the area under the curve is much closer to 0.66
(romberg's result) than to 0.02 (as integrate would
have us believe).

The same problem occurs if we use defint instead of
integrate.

Cheers.

Discussion

  • Robert Dodier

    Robert Dodier - 2006-07-31

    Logged In: YES
    user_id=501686

    Observed in 5.9.3cvs. Not sure, but it looks like integrate
    yields a different result when A and B are symbols compared
    to when they are given specific values A=2, B=3.

     
  • Robert Dodier

    Robert Dodier - 2006-07-31
    • labels: --> Lisp Core - Integration
     
  • Dan Gildea

    Dan Gildea - 2008-11-26
    • status: open --> closed
     
  • Dan Gildea

    Dan Gildea - 2008-11-26

    fixed in risch.lisp rev 1.16 - now returns unevaluated.

     

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