wxMaxima version: 13.4.0
Maxima version: 5.31.1
Maxima build date: 2013-09-24 09:49:12
Host type: i686-pc-mingw32
Lisp implementation type: GNU Common Lisp (GCL)
Lisp implementation version: GCL 2.6.8
(declare(n,integer),assume(n>3,a>0,k>0),integrate(r^(n-1)*exp(-(a-%i*k)*r),r,0,inf))
asks redundant questions is n-1 positive
when I just said it was >3
Also it does not solve the integral which has a very easy answer of (n-1)!/(a-%i*k)^n
which it does give when replace a-%i*k
by just a
Diff:
is that latest version you tested which did not come back with ridiculous questions used in Linux or windows and what version?
Do you know of any issues or bugs worse in the 5.33 than 5.31.1 ?
On Saturday, August 9, 2014 11:05 AM, Robert Dodier robert_dodier@users.sf.net wrote:
Diff:
--- old +++ new @@ -5,7 +5,10 @@ Lisp implementation type: GNU Common Lisp (GCL) Lisp implementation version: GCL 2.6.8 -(declare(n,integer),assume(n>3,a>0,k>0),integrate(r^(n-1)exp(-(a-%ik)r),r,0,inf)) asks redundant questions is n-1 positive when I just -said it was >3 -Also it does not solve the integral which has a very easy answer of (n-1)!/(a-%ik)^n -which it does give when replace a-%ik by just a +~~~~ +(declare(n,integer),assume(n>3,a>0,k>0),integrate(r^(n-1)exp(-(a-%ik)r),r,0,inf)) +~~~~ + +asks redundant questions
is n-1 positive
when I just said it was >3 + +Also it does not solve the integral which has a very easy answer of(n-1)!/(a-%i*k)^n
which it does give when replacea-%i*k
by justa
________
[bugs:#2797] asks redundant questions
Status: open
Group: None
Created: Sat Aug 09, 2014 01:48 AM UTC by dan hayes
Last Updated: Sat Aug 09, 2014 01:48 AM UTC
Owner: nobody
wxMaxima version: 13.4.0
Maxima version: 5.31.1
Maxima build date: 2013-09-24 09:49:12
Host type: i686-pc-mingw32
Lisp implementation type: GNU Common Lisp (GCL)
Lisp implementation version: GCL 2.6.8
(declare(n,integer),assume(n>3,a>0,k>0),integrate(r^(n-1)exp(-(a-%ik)r),r,0,inf))
asks redundant questions is n-1 positive when I just said it was >3
Also it does not solve the integral which has a very easy answer of (n-1)!/(a-%ik)^n which it does give when replace a-%i*k by just a
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Related
Bugs:
#2797Redundant questions not observed in current version (post-5.33), therefore closing this report. Maxima still can't compute the integral, but that, while regrettable, is not a bug.